SSC CHSL 2013 · Question 142 of 207
h 45° 30° B D c x 10 m h Þ = From DABC, tan45° = h x x h h = In DABD, tan30° = + + x 10 h 10 1 h = + h 10 3 + h = 5( 3 1)m q - q 4 5sin 3cos
Source: SSC CHSL Solved Paper 20-10-2013 (Disha Publications) · reliable-secondary
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