SSC CHSL 2012 · Question 147 of 202
Circumradius of a triangle abc = ( )( )( )( ) + + + - + - + - a b c a b c b c a a c b ´ ´ 3 4 5 = ( )( )( )( ) + + + - + - + - 3 4 5 3 4 5 4 5 3 3 5 4 60 = 2.5 cm = ´ ´ ´ 12 2 6 4 125 100 ´ = x 100
Source: SSC CHSL Solved Paper 04-11-2012 (Disha Publications) · reliable-secondary
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