SSC CHSL 2012 · Question 142 of 202
DABC is an isocoles triangle. Therefore, AC = BC = 5 cm 5 cm Now, AB2 = AC2 + BC2 C B + = AB2 = 52 + 52 Þ 25 25 5 2 cm
Source: SSC CHSL Solved Paper 04-11-2012 (Disha Publications) · reliable-secondary
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