SSC CHSL 2012 · Question 136 of 202
Time difference between 9.00 A.M & 2.00 P.M = 5 hours Temperature difference between 21°C & 36°C = 36 – 21 = 15°C Now, Time difference between 9.00 A.M & 12.00 Noon = 3 hrs. temperature ¾¾¾¾¾¾® ° In 5 hours 15 C difference temperature æ ö 15 ¾¾¾¾¾¾® So, In 3 hours ø = 9°C ´ 3 ç ÷ è difference 5 So, temperature at noon = 21 + 9 = 30°C
Source: SSC CHSL Solved Paper 04-11-2012 (Disha Publications) · reliable-secondary
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