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SSC CHSL 2012 · Question 136 of 202

From 9.00 AM to 2.00 PM, the temperature rose at a constant rate from 21ºC to 36ºC. What was the temperature at noon ?

  1. A27ºC
  2. B30ºCCorrect
  3. C32ºC
  4. D28.5ºC

Answer: B. 30ºC

Explanation

Time difference between 9.00 A.M & 2.00 P.M = 5 hours Temperature difference between 21°C & 36°C = 36 – 21 = 15°C Now, Time difference between 9.00 A.M & 12.00 Noon = 3 hrs. temperature ¾¾¾¾¾¾® ° In 5 hours 15 C difference temperature æ ö 15 ¾¾¾¾¾¾® So, In 3 hours ø = 9°C ´ 3 ç ÷ è difference 5 So, temperature at noon = 21 + 9 = 30°C

Source: SSC CHSL Solved Paper 04-11-2012 (Disha Publications) · reliable-secondary

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