SSC CHSL 2012 · Question 133 of 202

ABC is a right angled triangle, right angled at C and p is the length of the perpendicular from C on AB. If a, b and c are the lengths of the sides BC, CA and AB respectively, then 1 1 1 = -

A2 2 2 p b a 1 1 1 = +
B2 2 2 p a b 1 1 1 + =Correct
C2 2 2 p a b 1 1 1 = -
D2 2 2 p a b

Answer: B. 2 2 2 p a b 1 1 1 + =

Explanation

Here, ÐACB = 90° ÐADC = 90° ÐBDC = 90° C a b p B A c D Triangles ACB, ADC and BDC are right angle triangles. Here, Area of DABC = Area of DADC + Area of DBDC 2012 Solved Paper

Source: SSC CHSL Solved Paper 04-11-2012 (Disha Publications) · reliable-secondary

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