The sum of 5 consecutive odd numbers of set-A is 185. What will be the average of Set-B containing 4 consecutive even numbers, if the smallest number of Set-B is 13 more than the highest number of Set-A.

Explanation

Let the five consecutive odd numbers in Set A be $$(x) , (x+2) , (x+4) , (x+6) , (x+8)$$ Sum of these numbers = $$(x) + (x+2) + (x+4) + (x+6) + (x+8) = 185$$ => $$5x + 20 = 185$$ => $$5x = 185 - 20 = 165$$ => $$x = \frac{165}{5} = 33$$ => Highest number in Set A = $$(x + 8) = 33 + 8 = 41$$ => Smallest number in Set B = $$41 + 13 = 54$$ Now, 4 consecutive even numbers in Set B starting from 54 = 54,56,58,60 Sum of numbers in Set B = 54 + 56 + 58 + 60 = 228 $$\therefore$$ Required average = $$\frac{228}{4} = 57$$