RRB NTPC 2026 · Question 80 of 93
Given 87 = 3 × 29 Concept Used A number divisible by 87 must be divisible by 3 and 29 Formula Used Divisibility rules for 3 and 29 Solution 8004 : 8 + 0 + 0 + 4 = 12 => divisible by 3 8004 ÷ 29 = 276 => divisible by 29 8088 : 8 + 0 + 8 + 8 = 24 => divisible by 3 8088 ÷ 29 = integer 7150 : 7 + 1 + 5 + 0 = 13 => not divisible by 3 7835 : 7 + 8 + 3 + 5 = 23 => not divisible by 3 Final Answer 8004
Source: RRB NTPC CBT-I Memory-Based Paper 16 March 2026 S1 (careerpower test-platform compilation) · memory-based
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