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  9. Q78

RRB NTPC 2026 · Question 78 of 93

Which smallest number should be added to 25553 so that the sum is completely divisible by 38?

  1. A21Correct
  2. B22
  3. C23
  4. D18

Answer: A. 21

Explanation

Given: Number = 25553 Divisor = 38 Formula Used: Required number = Divisor - Remainder Solution: 25553 ÷ 38 = 672 remainder 17 Required number = 38 - 17 = 21

Source: RRB NTPC CBT-I Memory-Based Paper 16 March 2026 S1 (careerpower test-platform compilation) · memory-based

← Q77View full paper (93 questions)Q79 →

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