RRB NTPC 2022 · Question 96 of 110
Let the number is a and b. ATQ- a+b =17 a2+b2 =157 (a+b)2 = a2+b2 +2ab. 17×17 =157+2ab 2ab =289-157=132. ab =66 (11,6) is the prime factor of 66. So, a=11, and b =6 Now, a3+b3=1331+216=1547.
Source: RRB NTPC 2022 CBT 2 Previous Year Paper (12-June-2022) — ixambee compilation with answer key · reliable-secondary
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