RRB NTPC 2022 · Question 82 of 110

If √3 tan 2θ – 3 = 0, then find the value of tanθ secθ – sinθ where 0 θ 90°

Answer: D. 1/6

√3 tan 2θ – 3 = 0 √3 tan 2θ =3 tan 2θ=tan60° compare both sides- 2θ =60° θ =30° Now- tanθ secθ – sinθ put the value of θ. tan30° sec30° – sin30°

Source: RRB NTPC 2022 CBT 2 Previous Year Paper (12-June-2022) — ixambee compilation with answer key · reliable-secondary

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