RRB NTPC 2022 · Question 110 of 110
Let the common ratio be x. Hence, the length, width, and height of the cuboid are 4x, 3x, and 5x respectively. According to the question, 4 × (4x + 3x + 5x) = 144 x = 3 Hence, the surface area of the cuboid = 2 (4x × 3x + 4x × 5x + 3x × 5x) = 2x2 (12 + 20 + 15) =2×32×47 =9×94 =846cm2
Source: RRB NTPC 2022 CBT 2 Previous Year Paper (12-June-2022) — ixambee compilation with answer key · reliable-secondary
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