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  9. Q70

RRB NTPC 2021 · Question 70 of 131

The least number which on being divided by 2, 3, 4, 5, and 6 leaves a remainder of 1 but no remainder when divided by 7 is:

  1. A322
  2. B315
  3. C308
  4. D301Correct

Answer: D. 301

Explanation

LCM of 2, 3, 4, 5, and 6 =60 ATQ- The number will be divided by 7 and divided by 2,3,4,5,6 leaves the remainder 1. 60×5+1=301.

Source: RRB NTPC 2021 CBT 1 Previous Year Paper (3 Feb) — ixambee compilation with answer key · reliable-secondary

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