The population of a town is 10,000. If the male population increases by 5% and the female population by 10%, the population will become 10,800. How much of the town's present population is female?

Explanation

Let the number of men =x Female =10,000-x ATQ- 5x+100000-10x =80000. -5x =2000 X =4000. Female =10000-4000=6000. Second method- Let the number of males =100x And female =100y ATQ- x+y =100 … (1) ×5 5x+10y =800 … (2) 5x+5y =500 … (3) Solving EQ (1) and EQ (2). 5y =300 Y=60. Number of females =100×60 =6000.