Who among the following is the first Tirthankara of Jainism?

Explanation

Rishabhanatha is the first Tirthankara of Jainism and the founder of Ikshvaku dynasty. The first Tirthankara, Rishabhanatha is mentioned in Hindu texts like the Rigveda, Vishnupurana and Bhagwata Purana. The Vishnu Purana and Bhagavat Purana describes Rishabha as an incarnation of Narayana. Logical Reasoning 1. Mary Kom is related to Boxing in the same way as Bajrang Punia is related to a) Athletics b) Wrestling c) Fencing d) Gymnastics Answer: B Sports Personality – Field. 2. An equation followed by two conclusions is given below. Statement: A ≥ B ≤ C > H = O ≥ M Conclusions: I. C ≥ M II. O > B Choose the correct option. a) Only I is true. b) Only II is true. c) Both I and II are true. d) Neither I nor II is true. Answer: D I. C ≥ M → False (As, C > H = O ≥ M → C > M) II. O > B → False (As, B ≤ C > H = O → Relation between O and B cannot be determined) Direction (3 – 5): Read the given information and answer the questions based on it. Eight friends Arjun, Nakul, Bhim, Duryodhan, Abhimanyu, Shakuni, Karna and Rahul are standing in a row facing north. Karna is to the left of Duryodhan but not at its immediate left. Arjun and Abhimanyu are immediate neighbours. No one sits to the left of Bhim. Nakul is third to the left of for RRB NTPC for RRC Level 1 9 Arjun. Only two person sits between Shakuni and Duryodhan. Abhimanyu is immediate neighbour of Shakuni but Shakuni does not sits in between any two people. Rahul is not adjacent to Arjun. 3. Nakul is adjacent to _________. a) Rahul and Duryodhan. b) Karna and Rahul. c) Rahul and Arjun. d) Bhim and Karna. Answer: B 4. How many people are in between Abhimanyu and Shakuni? a) 0 b) 1 c) 2 d) 3 Answer: A 5. Who is second to the right of Bhim? a) Rahul b) Karna c) Nakul d) Arjun Answer: C 6. Complete the analogy. AGHD : DDLZ : RAJA : ? a) UNXW b) UXNW c) UXNX d) UWNX Answer: B A + 3 = D G – 3 = D H + 4 = L D – 4 = Z Similarly, R + 3 = U A – 3 = X J + 4 = N A – 4 = W 7. Read the given statements and conclusions carefully. Assuming that the information given in the statements is true, even if it appears to be at variance with commonly known facts, decide which of the given conclusions logically follow(s) from the statements. Statements: I. All H is F II. All F is G Conclusions: I. Some G is H II. All G is H a) Only conclusion II follows b) Only conclusion I follows c) Neither conclusion I nor II follows d) Both conclusions I and II follow Answer: B for RRB NTPC for RRC Level 1 10 I. Some G is H - True II. All G is H - False 8. A statement followed by two assumptions is given below. Statement: What a fool I am to rely on a trickster like Soham! Assumptions: I. Soham is unreliable. II. I am a fool. Choose the correct alternative. a) Only I is implicit. b) Only II is implicit. c) Both I and II are implicit. d) Neither I nor II is implicit. Answer: C 9. Guru is granddaughter of Dhruv. Arya is sister-in-law of Zahir whose only brother is Hemant. If Zahir is uncle of Guru and unmarried, then how is Hemant related to Arya? a) Brother-in-law b) Father-in-law c) Husband d) Son Answer: C 10. A statement followed by two conclusions is given below. Statements: Money plays a vital role in politics. Conclusion: I. The poor can never become politicians. II. All the rich men take part in politics. Choose the correct option. a) Only conclusion II follows b) Only conclusion I follows c) Neither conclusion I nor II follows d) Both conclusions I and II follow Answer: C 11. Select the number that will come next in the following series. 2, 2, 3, 4, 5, 6, 7, ? a) 7 b) 8 c) 6 for RRB NTPC for RRC Level 1 11 d) 11 Answer: B Split the series into two parts: Odd part: 2, 3, 5, 7 (Prime number series) Even part: 2, 4, 6, 8 (Even number series) 12. If we interchange “+” with “–” and “÷” with “×”, then what is the value of the below expression? 39 × 3 + 10 – 13 ÷ 2 a) 3 b) 17 c) 29 d) 31 Answer: C + ÷ - × 39 × 3 + 10 – 13 ÷ 2 If we interchange “+” with “–” and “÷” with “×” then = 39 ÷ 3 - 10 + 13 × 2 = 13 – 10 + 26 = 39 – 10 = 29 13. Identify the diagram that best represents the relationship among the given classes. Actor, Dancer, Singer a) b) c) d) Answer: D 14. An assertion (A) and a reason (R) are given below. Assertion (A): Himalayas once laid under the sea. Reason (R): Fossils of marine creatures are traced on the Himalayas. Choose the correct option. a) A and R both are true and R is the correct explanation of A. b) A and R both are true and R is not the correct explanation of A. c) A is true but R is false. d) A is false but R is true. Answer: A 15. Find the ODD one out from the given options. a) G b) J c) T d) P Answer: A a) G = 7 b) J = 10 c) T = 20 d) P = 16 for RRB NTPC for RRC Level 1 12 The place value of ‘G’ is odd number, while the place value of other letters is an even number. 16. Three of the following four sets are related in a certain way and one is different from the rest. Select the odd one out. a) (4, 56, 14) b) (3, 12, 4) c) (19, 57, 13) d) (71, 852, 12) Answer: C a) (4, 56, 14) → 4 × 14 = 56 b) (3, 12, 4) → 3 × 4 = 12 c) (19, 57, 13) → 19 × 13 ≠ 57 d) (71, 852, 12) → 71 × 12 = 852 17. In a certain language, TESLA is written as 100, OVER is written as 48, then how will WESTERN be written as in that code? a) 294 b) 225 c) 249 d) 252 Answer: A Number of letters in TESLA is 5 and 52 = 25 25 × (Number of letters – 1) = 25 × (5 – 1) = 25 × 4 = 100 Number of letters in TESLA is 4 and 42 = 16 = 16 × (Number of letters – 1) = 16 × (4 – 1) = 16 × 3 = 48 Similarly, Number of letters in WESTERN is 7 and 72 = 49 = 49 × (Number of letters – 1) = 49 × (7 – 1) = 49 × 6 = 294 18. An assertion (A) and a reason (R) are given below. Assertion (A): An atom is neutral despite the charged particles in it. Reason (R): The neutrons do not have any charge. Choose the correct option. a) A and R both are true and R is the correct explanation of A. b) A and R both are true and R is not the correct explanation of A. c) A is true but R is false. d) A is false but R is true. Answer: B 19. Find the wrong term in the series. 78.50, 22.5, 9, 6, 12 a) 22.5 b) 6 c) 78.50 d) 12 Answer: C 78.50, 22.5, 9, 6, 12 Write the series from right end to left end: 12, 6, 9, 22.5, 78.50 12 × 0.5 = 6 6 × 1.5 = 9 18 × 2.5 = 22.5 45 × 3.5 = 78.75 for RRB NTPC for RRC Level 1 13 20. Read the given statements and conclusions carefully. Assuming that the information given in the statements is true, even if it appears to be at variance with commonly known facts, decide which of the given conclusions logically follow(s) from the statements. Statements: I. Some forests are not desert. II. Some desert is Sandy. Conclusions: I. No forest is Sandy. II. Some desert is forest. a) Only conclusion II follows b) Only conclusion I follows c) Either conclusion I or II follows d) None follows Answer: D I. No forest is Sandy. - False II. Some desert is forest. - False 21. Select the term that will replace ‘?’ in the following series. a) ZYD b) YZD c) DZY d) ZDY Answer: A R + 2 = T; T + 2 = V; V + 2 = X; X + 2 = Z E + 5 = J; J + 5 = O; O + 5 = T; T + 5 = Y P – 3 = M; M – 3 = J; J – 3 = G; G – 3 = D 22. A statement followed by two arguments is given below. Statement: Video libraries are flourishing very much these days. Conclusions: I. People in general have got a video craze. II. It is much cheaper to see as many movies as one likes on videos rather than going to the cinema hall. a) Only conclusion II follows b) Only conclusion I follows c) Neither conclusion I nor II follows d) Both conclusions I and II follow Answer: D 23. Which one is different from the rest? a) Chess b) Cricket c) Hockey d) Football Answer: A Chess is an indoor game, while others are outdoor games. 24. If ‘+’ represents ‘×’, ‘-‘ represents ‘+’, ‘×’ represents ‘÷’ and ‘÷’ represents ‘-‘, then find the value of the following expression. 12 + 3 × 4 – 6 = ? a) 5 b) 15 c) 10 d) 4 Answer: B + - × ÷ × + ÷ - for RRB NTPC for RRC Level 1 14 Given: 12 + 3 × 4 – 6 = ? After replacing the symbols, we get: = 12 × 3 ÷ 4 + 6 = 9 + 6 = 15 25. Agastya is facing south. He first moved 180 in clockwise direction, then 270 in clockwise direction and finally 390 in anti-clockwise direction. Which direction is he facing now? a) North-East b) South-West c) North-West d) South-East Answer: B Directions (26 – 27): Read the given data and answer the questions based on it. If circle represents chocolate lovers, rectangle represents toffee lovers and triangle represents cupcake lovers, then 26. The letter A represents: a) People who like both chocolate and toffee but not cup cake. b) People who like toffee, cupcake and chocolate. c) People who like only chocolate. d) People who like cupcake but not toffee. Answer: B 27. Only toffee lovers is represented by the letter/letters: a) C, F b) F c) G, F d) C Answer: A 28. Select the number from the options given below that will replace the ‘?’ in the following matrix. 14 28 18 20 20 ? 30 14 16 a) 30 b) 45 c) 25 d) 20 Answer: D Row 1: 14 + 28 + 18 = 60 Row 3: 30 + 14 + 16 = 30 Similarly, Row 2: 20 + 20 + ? = 60 => 40 + ? = 60 => ? = 60 – 40 => ? = 20 for RRB NTPC for RRC Level 1 15 29. Which of the following letter clusters follows the difference of 12, 4, 5. a) SVZO b) PBHR c) KWYE d) LXBG Answer: D d) LXBG → L + 12 = X; X + 4 = B; B + 5 = G 30. Which two signs should be interchanged to make the below equation mathematically correct? 12 – 3 + 8 × 2 ÷ 4 = 16 a) ÷ and × b) × and - c) + and - d) ÷ and - Answer: D 12 – 3 + 8 × 2 ÷ 4 = 16 d) ÷ and - =12 ÷ 3 + 8 × 2 - 4 = 4 + 16 – 4 = 16 Mathematics 1. A perimeter of square is 44 cm and circumference of circle is 44 cm. whose area is greater? a) A2 > A1 b) A2 A1 2. A cost price of an article is Rs. 120/- at loss of 10%. Find the selling price. a) Rs. 90/- b) Rs. 108/- c) Rs. 100/- d) Rs. 120/- Answer: B Loss% = (CP - SP)/ CP × 100 10 = (1 – SP/CP) × 100 10/100 = (1 – SP/CP) 1/10 = (1 – SP/CP) 1 - 1/10 = SP/CP 9/10 = SP/CP 9/10 = SP/120 SP = 108/- 3. 6 pipes fill the tank in 1 hour 20 minutes. 5 pipes fill the tank in how many minutes? a) 1 hour 15 minutes b) 1 hour 30 minutes c) 1 hour 36 minutes for RRB NTPC for RRC Level 1 16 d) 1 hour 26 minutes Answer: C According to the question, 6 pipes × 1 hour 20 minutes = 5 pipes × x hours 6 × (1 + 1/3) = 5 × x 6 × 4/3 = 5x x = 24/15 = 8/5 × 60 = 1 hour 36 minutes 4. What should be multiply with 288 to make it perfect square? a) 3 b) 4 c) 5 d) 6 Answer: D Factors of 288 = 2 × 2 × 2 × 2 × 2 × 3 × 3 So, 288 should be multiply with 6 to make it perfect square. 5. Volume of cylinder is equal to volume of cone and height of cylinder is equal to height of cone. Find the ratio of radius. a) 1/√3 b) 1/√2 c) 1/3 d) 1/2 Answer: A Volume of Cylinder = Volume of Cone π × r12 × h1 = (π × r22 × h2)/3 r12 = r22/3 r12 : r22 = 1/3 r1 : r2 = 1/√3 6. 3a = 4b = 6c and a + b + c = 27√29. Find the value of √ a2 + b2 + c2. a) 61 b) 29 c) 87 d) 54 Answer: C 3a = 4b = 6c a : b : c = 4 : 3 : 2 a + b + c = 27√29 4x + 3x + 2x = 27√29 9x = 27√29 x = 3√29 a = 4x = 12√29 b = 3x = 9√29 c = 2x = 6√29 a2 = 144 × 29 b2 = 81 × 29 c2 = 36 × 29 √ a2 + b2 + c2 = √261 × 29 = 87 7. Ratio of two numbers is 3 : 4. HCF is 4. Find the LCM. a) 3 b) 12 c) 16 d) 48 Answer: D LCM/HCF = a × b LCM/4 = 12 LCM = 12 × 4 = 48 8. Find the value of tan (13π/12). a) (√3 + 1) b) (√3 - 1) c) (√3 - 1)/ (√3 + 1) d) (√3 + 1)/ (√3 - 1) Answer: C Tan (13π/12) = tan (13 × 180/12) for RRB NTPC for RRC Level 1 17 = tan (13 × 15°) = tan (195°) = tan (180° + 15°) = tan 15° = (√3 - 1)/ (√3 + 1) 9. Ratio of number of coins of 1Rs, 50 paisa and 25 paisa is 3 : 4 : 5. How many 50 paisa coins are there in a bag of Rs.93.75? a) 45 b) 60 c) 45 d) 75 Answer: B 300x + 200x + 125x = 9375 625x = 9375 x = 9375/625 x = 15 No. of 50 paisa coins = 4 × 15 = 60 10. 1.5x = 0.04 y. Find the value of (y - x)/ (y + x). a) 73/75 b) 75/73 c) 75/77 d) 73/77 Answer: D 1.5x = 0.04 y x/y = 4/150 = 2/75 x = 2/75 y = (y - x)/ (y + x) = (y – 2/75y)/ (y + 2/75y) = 73/77 11. 10% of m = 20% of n. Find the ratio of m and n. a) 2 : 1 b) 1 : 2 c) 3 : 2 d) 2 : 3 Answer: A 10% of m = 20% of n m : n = 2 : 1 12. Diameter of wheel is 14/11 m. A wheel take 10 revolve in 1 minute. Find the speed (in kmph). a) 3 kmph b) 2.4 kmph c) 5.4 kmph d) 2.8 kmph Answer: B Distance = n × (2πr) = Speed × Time = 10 × (2 × 22/7 × 14/11) = Speed × 1 Speed = 40 m/min = 40/1000 × 60 = 2.4 kmph 13. In a map, 1 cm is equal to 9 km. Then 2 cm is equal to how many km. a) 0.9 km b) 9 km c) 18 km d) 1.8 km Answer: C 1 cm = 9 km 2 cm = 18 km 14. In a ratio of rice and sugar 2/3 part is rice. Find the percent of sugar. a) 33.34% b) 66.67% c) 12.25% d) 34.25% Answer: A Rice : Sugar = 2/3 : 1/3 % Sugar = 1/3 × 100 = 33.34% for RRB NTPC for RRC Level 1 18 15. Kavita travels with 5/6th of its original speed and take 2 minute more to reach on destination. Find the original time. a) 17 minute b) 15 minute c) 12 minute d) 10 minute Answer: D Speed = 6 5 Time = 5 6 1 = 2 minute Original Time = 5 × 2 = 10 minute 16. One complimentary angle is 3 times of other complimentary angle. Find the angle. a) 67° and 22° b) 65° and 25° c) 62.5° and 22.5° d) 67.5° and 22.5° Answer: D Sum of two complimentary angle = 90° θ1 + θ2 = 90° θ1 : θ2 = 3 : 1 3x + x = 90° 4x = 90° x = 90°/4 = 22.5° 3x = 3 × 22.5° = 67.5° 17. Which of the following will never be negative? a) Mode b) Median c) Mean d) Standard Deviation Answer: D 18. Find the sum of four least prime numbers. a) 17 b) 15 c) 12 d) 19 Answer: A Sum = 2 + 3 + 5 + 7 = 17 19. Find the HCF of two even prefect square. a) 16 b) 64 c) 4 d) 32 Answer: C HCF of 4 and 16 = 4 20. Ratio of boys and girls is 5 : 7. Girls are 6 more than boys. Find the number of boys and girls. a) 7 and 8 b) 15 and 21 c) 21 and 15 d) 14 and 15 Answer: B Boys : Girls = 5 : 7 Girls = 6 + Boys 7x = 6 + 5x 7x – 5x = 6 2x = 6 x = 6/2 x = 3 Boys = 5 × 3 = 15 Girls = 7 × 3 = 21 21. Area of square is formed using wire is 81 cm2. What is the area of semi-circle formed using same wire? a) 20 cm2 b) 77 cm2 c) 154 cm2 d) 37 cm2 for RRB NTPC for RRC Level 1 19 Answer: B Area of square = 81 cm2 a2 = 81 a = 9 cm Perimeter of square = 4a = 4 × 9 = 36 cm Length of the wire is 36 cm So, circumference of semi-circle = 36 cm 22/7r + 2r = 36 r (22/7 + 2) = 36 r (36/7) = 36 r = 7 cm Area of semi-circle = πr2/2 = 22/7 × 72/2 = 77 cm2 22. Two numbers are 32 and 40. HCF is 4. Find the LCM. a) 400 b) 320 c) 250 d) 350 Answer: B LCM × HCF = First Number × Second Number LCM × 4 = 32 × 40 LCM = 320 23. Diameter and height of cone is 8 cm and 14 cm. Find the lateral surface area. a) 156 cm2 b) 105 cm2 c) 183 cm2 d) 188 cm2 Answer: C Lateral Surface Area = π × r × l = 22/7 × 4 × √212 = 183 cm2 24. Simplify: 108 ÷ (36 × 1/4) + 2/5 × 3 (1/4). a) 15 b) 14.3 c) 12 d) 13.3 Answer: D 108 ÷ (36 × 1/4) + 2/5 × 3 (1/4) = 108 ÷ 9 + 2/5 × 13/4 = 12 + 13/10 = 12 + 1.3 = 13.3 25. Total 2401 trees are planted in a square field. Find the number of trees planted in one row of square field. a) 28 b) 7 c) 49 d) 14 Answer: C x2 = 2401 x = 49 Number of trees planted in one row is 49. 26. Variance of 20 numbers is ‘f’. Every numbers is multiply by 2. What is the new variance? a) 4f b) 2f c) f d) f/2 Answer: B Variance of 20 numbers = ‘f’ 2 × 20 = 2f If every numbers is multiply by 2 then variance is ‘2f’. 27. Mean of 100 numbers is 40. A number 40 is replaced by 50. Find the new mean. a) 40 b) 42 for RRB NTPC for RRC Level 1 20 c) 40.1 d) 41 Answer: C Mean = 40 + 10/100 = 40 + 0.1 = 40.1 28. Perimeter of 5 square is 24, 32, 40, 76 and 80 respectively. Area of 6th square is equal to sum of area of five squares. Find the perimeter of 6th square. a) 87 cm b) 95 cm c) 124 cm d) 148 cm Answer: C According to the question, Area of 6th square = 62 + 82 + 102 + 192 + 202 a2 = 36 + 64 + 100 + 361 + 400 a2 = 961 a = 31 cm Perimeter of 6th square = 4a = 4 × 31 = 124 cm 29. Cos θ = - 3/5. Find the value of sin θ in same quadrant. a) – 3/4 b) - 4/5 c) - 3/5 d) – 4/3 Answer: B Cos θ = -3/5 = base/hypotenuse Perpendicular = 4 Sin θ = - 4/5 30. a/2 = b/3 = c/5. Find the value of (a + b + c)/c. a) 2 b) 3 c) 4 d) 5 Answer: A a/2 = b/3 = c/5 = k (let) a = 2k, b = 3k, c = 5k (a + b + c)/c = (2k + 3k + 5k)/5k = 10k/5k = 2