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RRB Junior Engineer / DMS / CMA 2019 · Question 91 of 3719

Find the greatest number of 4 digits divisible by 15, 25, 40 and 75.

Mathematics - Number System

  1. Aa. 9600Correct
  2. Bb. 9400
  3. Cc. 9000
  4. Dd. 9200

Answer: A. a. 9600

Explanation

The greatest number of 4 digits is 9999. LCM of 15, 25, 40, and 75 is 600. On dividing 9999 by 600, the remainder is 399. Then, Required number (9999 - 399) = 9600.

Source: RRB JE 2019 CBT-1 (24-May-2019 Shift-1) — ixambee compilation with answer key and solutions · reliable-secondary

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