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RRB Junior Engineer / DMS / CMA 2019 · Question 41 of 3719

If a, 1, b are in arithmetic progression and 1, a, b are in geometric progression, then a and b are respectively equate to _______ (where a ≠ b).

Mathematics - Miscellaneous

  1. Aa. 2, 4
  2. Bb. -2, 4Correct
  3. Cc. 4, 1
  4. Dd. -1, 2

Answer: B. b. -2, 4

Explanation

Given a, 1, and b are in AP and 1, a, and b are in GP: From AP= 1- a=b-1 b=2- a … (1) From GPb = a² … (2) from Eq (1) and Eq (2) a² = 2-a a²+a-2=0 a2+2a- a -2 =0 a = 1 or - 2 Since a ≠ 1: a = -2 b = a² = 4 So, a = -2 and b = 4. Alternate methodAccording to the option(a + b)/2 = 1 (a + b) = 2 Put the value of a and b in the option and satisfied. Taking option 2. (-2 + 4) = 2 2 = 2 (satisfied)

Source: RRB JE 2019 CBT-1 (24-May-2019 Shift-2) — ixambee compilation with answer key and solutions · reliable-secondary

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