PYQPulse
HomeMocksPracticePYQsUpdatesDashboard
PYQPulse

Timing-accurate mock tests and PYQs for SSC, Banking and Railway exams — so the real paper feels like a revision.

Exams

  • SSC exams
  • Banking exams
  • Railway exams
  • All exams

Practice

  • Practice questions
  • Mock test series
  • Sectional tests
  • Year-wise PYQs
  • Performance analytics

Company

  • About us
  • Help Centre
  • Pricing
  • Sign in

Legal

  • Privacy Policy
  • Terms of Service

Contact

  • hello@testwala.co.in
  • Telegram
  • +91 62816 87760

Practice interface modeled on the official exam pattern — not the official examination. PYQPulse is not affiliated with the Staff Selection Commission, IBPS, SBI, RBI, NABARD, SEBI or Indian Railways.

© 2026 PYQPulse. All rights reserved.

Built for aspirants, by aspirants.

HomeMocksPracticeStats
  1. Home
  2. ›
  3. PYQs
  4. ›
  5. RRB Junior Engineer / DMS / CMA
  6. ›
  7. 2019
  8. ›
  9. Q3604

RRB Junior Engineer / DMS / CMA 2019 · Question 3604 of 3719

If an integer needs two bytes of storage, then the maximum value of the signed integer is

  1. A2 16 – 1
  2. B2 15 – 1Correct
  3. C2 15
  4. D2 16

Answer: B. 2 15 – 1

Explanation

Concept: In signed form, for n bits Minimum number = –2 n-1 – 1 Maximum number = 2 n-1 – 1 Calculation: 1 byte = 8 bits 2 byte = 16 bits Maximum number = 2 n-1 – 1 = 2 16-1 – 1 = 2 15 – 1

Source: RRB JE 2019 (CBT 2) (IT) Previous Year Paper (30 Aug 2019) — prepp.in solved-paper PDF (answer key with explanations) · reliable-secondary

← Q3603View full paper (3719 questions)Q3605 →

Practice the full RRB Junior Engineer / DMS / CMA 2019 paper

Timed test with all 3719 questions, just like the real exam.

Start test