RRB Junior Engineer / DMS / CMA 2019 · Question 3555 of 3719
Explanation: Streamline: Potential line: u = ,v = − ∂y ∂ψ ∂x ∂ψ dψ = dx + ∂x ∂ψ dy = ∂y ∂ψ 0 = dx dy − = ∂y ∂ψ ∂x ∂ψ u v u = ,v = ∂x ∂ϕ ∂y ∂ϕ The slope of the velocity potential The slope of the stream-line Hence, they are orthogonal to each other (∵ m 1m 2 = -1)
Source: RRB JE 2019 (CBT 2) (ME) Previous Year Paper (31 Aug 2019) — prepp.in solved-paper PDF (answer key with explanations) · reliable-secondary
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