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RRB Junior Engineer / DMS / CMA 2019 · Question 3443 of 3719

A hollow steel column has to carry an axial load of 2,00,000 kg and the ultimate stress for the steel column is 4800 kg/cm 2and allows a load factor of 4. What is the sectional area of the column?

  1. A196.66 cm 2
  2. B166.66 cm 2Correct
  3. C180.66 cm 2
  4. D176.66 cm 2

Answer: B. 166.66 cm 2

Explanation

Explanation:- The stress is given as, where, stress is the ratio of ultimate stress to the factor of safety, i.e. Calculations:- Given:- Axial load P = 200000 kg, Ultimate stress σ u= 4800 kg/cm 2, Factor of safety n = 4 Now, Working stress = 1200 kg/cm 2 A = 166.66 cm 2

Source: RRB JE 2019 (CBT 2) (ME) Previous Year Paper (31 Aug 2019) — prepp.in solved-paper PDF (answer key with explanations) · reliable-secondary

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