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RRB Junior Engineer / DMS / CMA 2019 · Question 2938 of 3719

D is a point on BC of $$\triangle$$ABC where BD = $$\left(\frac{1}{2}\right)$$DC. Find the ratio of areas of $$ \triangle $$ABD and $$ \triangle $$ABC.

  1. A3:1
  2. B1:3Correct
  3. C2:3
  4. D3:2

Answer: B. 1:3

Official answer key verified. Detailed explanation coming soon.

Source: RRB JE 2019 CBT-1 (30-May-2019 Shift 2) — cracku.in solved paper with answer key · reliable-secondary

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