RRB Junior Engineer / DMS / CMA 2019 · Question 24 of 3719
Mathematics - Number System
Let the positive integer be x, then 5x + 3 = 2x2 2x2 5x-3=0 2x²-6x+x-3 = 0 2x (x-3) + 1(x - 3) = 0 (2x + 1) (x - 3) = 0 Taking, (x - 3) = 0 x=3 So, the positive integer is 3.
Source: RRB JE 2019 CBT-1 (24-May-2019 Shift-2) — ixambee compilation with answer key and solutions · reliable-secondary
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