RRB Junior Engineer / DMS / CMA 2019 · Question 2 of 3719
Mathematics - Time and Distance
Let the speed of the boat be x km/h And the speed of the stream be y km/h Distance travel in Upstream is = (x - y) × 8(4/5) = (x - y) × 44/5 Distance travel in Downstream is= (x + y) × 4 Since the distance is the same – (x - y) x 44/5 = (x + y) x 4 11x - 11y = 5x + 5y 6x = 16y x/y = 8/3 x: y=8:3
Source: RRB JE 2019 CBT-1 (24-May-2019 Shift-2) — ixambee compilation with answer key and solutions · reliable-secondary
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