RRB Junior Engineer / DMS / CMA 2019 · Question 147 of 3719
Mathematics - Miscellaneous
Let the number be x. ATQ(153)2 – x3 = 1457 23409 – x3 = 1457 x3 = 23409-1457 = 21952 x = √ (21952) x = √ [2× 2× 2× 2× 2× 2 × 7 × 7 × 7] x=2×2×7 = 28
Source: RRB JE 2019 CBT-1 (24-May-2019 Shift-1) — ixambee compilation with answer key and solutions · reliable-secondary
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