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RRB Junior Engineer / DMS / CMA 2019 · Question 107 of 3719

John cycles at 10 km/h to reach his destination at 2 PM. If he travels at 15 km/h, he will reach at 12 noon itself. At what speed should he travel to reach the place at 1 PM?

Mathematics - Time and Distance

  1. Aa. 12 km/hCorrect
  2. Bb. 8 km/h
  3. Cc. 11 km/h
  4. Dd. 14 km/h

Answer: A. a. 12 km/h

Explanation

Time difference= 2PM -12 noon =2 hours ATQ10t = 15(t-2) 10t = 15t-30 30 =5t t = 6 hours Distance= d = 10t = 10 ×6 =60 km Time to reach by 1 PM= t-1 6-1= 5 hours Speed = 60 km /5 hours= 12 km/h

Source: RRB JE 2019 CBT-1 (24-May-2019 Shift-1) — ixambee compilation with answer key and solutions · reliable-secondary

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