RRB Junior Engineer / DMS / CMA 2015 · Question 2 of 480
Mathematics - Number System
Required number = HCF of (247 - 7) and (319-4) = HCF of 240 and 315 Here, 240 = 2x2x2x2x3x5 and 315 = 3x3x5x7 .-. HCFof240 and 315 = 3x5 = 15 .-. Required number = 15
Source: Arihant RRB JE Solved Paper 26-Aug-2015 (3rd Shift), Q91–150 — published solved-paper compilation (Q1–90 technical not included in this source) · memory-based
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