RRB Group D (Level-1 posts) 2022 · Question 95 of 598
Let: Distance (one way) = 20 km Going speed = 20 km/h Average speed for the round trip = 15 km/h Step 1: Calculate the Time Taken for the Journey Time taken to go: Since Gaurav covers 20 km at a speed of 20 km/h, the time taken for the journey going is: Time going = 2020km/h km = 1 hour Let the speed while returning be x km/h . Time taken to return: Time returning = 20xkm hours Step 2: Set Up the Average Speed Equation The formula for average speed over the round trip is: Average speed = Total distance Total time Since the total distance for the round trip is 40 km, and the average speed is 15 km/h: 15 = 1+4020 x Step 3: Solve for x Multiply both sides by 1 + 20 x : 15 (1 + 20 x ) = 40 15 + 300 x = 40 Subtract 15 from both sides: 300 x = 25 Now, solve for x : x = 300 25 = 12 km/h Answer: Gaurav’s speed while returning will be 12 km/h.
Source: RRB Group D 2022 Prev. Yr. Paper (17 Aug 2022) (Shift 1) - FreshersNow · reliable-secondary
Practice the full RRB Group D (Level-1 posts) 2022 paper
Timed test with all 598 questions, just like the real exam.
Start test