RRB Group D (Level-1 posts) 2022 · Question 9 of 598
To solve this problem, let’s break it down with the given conditions: 1. One year ago, the ratio of Saketh’s age to Tilak’s age was 5:6. 2. Four years hence, this ratio will be 6:7. Let’s denote: Saketh’s age one year ago as 5x. Tilak’s age one year ago as 6x. Step 1: Express the present ages of Saketh and Tilak in terms of x Since this was one year ago, their present ages will be: Saketh’s present age = 5x + 1 Tilak’s present age = 6x + 1 Step 2: Set up the equation based on the condition for ages four years hence Four years hence, their ages will be: Saketh’s age = 5x + 1 + 4 = 5x + 5 Tilak’s age = 6x + 1 + 4 = 6x + 5 According to the problem, the ratio of their ages four years hence is 6:7. Thus, (5x + 5) / (6x + 5) = 6 / 7 Step 3: Cross-multiply to solve for x We get: 7(5x + 5) = 6(6x + 5) Expanding both sides: 35x + 35 = 36x + 30 Rearrange to isolate x: 35 - 30 = 36x - 35x 5=x Step 4: Calculate Saketh’s present age Substitute x = 5 back into Saketh’s present age formula: 5x + 1 = 5(5) + 1 = 25 + 1 = 26 Answer: The present age of Saketh is 26 years.
Source: RRB Group D 2022 Prev. Yr. Paper (17 Aug 2022) (Shift 1) - FreshersNow · reliable-secondary
Practice the full RRB Group D (Level-1 posts) 2022 paper
Timed test with all 598 questions, just like the real exam.
Start test