RRB Group D (Level-1 posts) 2022 · Question 182 of 598
Step 1: Set Up the Problem Let CPCPCP be the cost price of the article. When James sells the article for 1,9201,9201,920, he makes a profit. The profit percentage can be expressed as: 1. Profit=SP1−CP=1920−CP\text{Profit} = SP_1 - CP = 1920 - CPProfit=SP1 −CP=1920−CP Profit Percentage=(1920−CPCP)×100\text{Profit Percentage} = \left(\frac{1920 - CP}{CP}\right) \times 100Profit Percentage=(CP1920−CP )×100 When James sells the article for 1,5001,5001,500, he incurs a loss. The loss percentage can be expressed as: 1. Loss=CP−SP2=CP−1500\text{Loss} = CP - SP_2 = CP - 1500Loss=CP−SP2 =CP−1500 Loss Percentage=(CP−1500CP)×100\text{Loss Percentage} = \left(\frac{CP - 1500}{CP}\right) \times 100Loss Percentage=(CPCP−1500 )×100 Step 2: Equate the Profit Percentage and Loss Percentage According to the problem, the percentage profit earned by selling at 1,9201,9201,920 equals the percentage loss suffered by selling at 1,5001,5001,500: 1920−CPCP×100=CP−1500CP×100\frac{1920 - CP}{CP} \times 100 = \frac{CP - 1500} {CP} \times 100CP1920−CP×100=CPCP−1500×100 Step 3: Simplify the Equation We can cancel out 100100100 from both sides: 1920−CPCP=CP−1500CP\frac{1920 - CP}{CP} = \frac{CP - 1500}{CP}CP1920−CP =CPCP−1500 Cross-multiplying gives: 1920−CP=CP−15001920 - CP = CP - 15001920−CP=CP−1500 Rearranging terms leads to: 1920+1500=2CP1920 + 1500 = 2CP1920+1500=2CP CP=34202=1710CP = \frac{3420} {2} = 1710CP=23420=1710 Step 4: Calculate the Selling Price for a 10% Profit To find the selling price for a 10% profit: Selling Price=CP+Profit\text{Selling Price} = CP + \text{Profit}Selling Price=CP+Profit Where profit is: Profit=10% of CP=10100×1710=171\text{Profit} = 10\% \text{ of } CP = \frac{10}{100} \times 1710 = 171Profit=10% of CP=10010×1710=171 Thus, the selling price should be: Selling Price=1710+171=1881\text{Selling Price} = 1710 + 171 = 1881Selling Price=1710+171=1881 Answer: The selling price if he wants to earn a 10% profit should be Rs 1,881.
Source: RRB Group D 2022 Prev. Yr. Paper (17 Aug 2022) (Shift 2) - Prepp · reliable-secondary
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