RPF Sub-Inspector (Executive) 2019 · Question 76 of 82
Let the first, second, third and fourth child get a, and d respectively. a = 2b = 3c = 4d = 12 (suppose) a=12, = 6, = 4, d = 3 12+6+4+3 = 25 units . 25 units = 550 1 unit = 22 Gift received by the first and second children = 12 + 6 = 18 units a ix = 18 22 = 396 .
Source: RPF SI Previous Year Paper 06-Jan-2019 — answer key & detailed solutions (ixambee PDF) · reliable-secondary
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