RBI Grade B Officer (General / DEPR / DSIM) 2023 · Question 83 of 260
Number Series
4 Detailed solution: The given number series follows the pattern of alternate addition and subtraction of cubes and squares, respectively. 74 + 6³ = 290 290 – 7² = 241 241 + 8³ = 753 753 – 9² = 672 672 + 10³ = 1672 1672 – 11² = 1551 So, 'P' = 1672. For I: Nearest perfect square number of 1672, is 41² = 1681 So, statement I is false. For II: 1672 ÷ 11 = 152 So, statement II is true. For III: P + 28 = 1672 + 28 = 1700 Since, 1700 = 34 X 50 So, statement III is true.
Source: RBI Grade B 2023 – Phase 1 recollected questions with answer key (EduTap compilation) · memory-based
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