8 men and 10 women can do a work in 15 days while 10 men and 18 women can do that work in 10 days. 4 men and 5 women started the work and after 10 days all men left the work then find how many more w…

Question

8 men and 10 women can do a work in 15 days while 10 men and 18 women can do that work in 10 days. 4 men and 5 women started the work and after 10 days all men left the work then find how many more women would be required to complete the whole work in 21 days?

PYQPulse · Accepted Answer

B. 15

PYQPulse · Answer

Explanation: Let the efficiency of a man be m units/day and efficiency of a woman be w units/day ATQ (8m+10w)× 15 = (10𝑚+ 18𝑤) × 10 𝑚 𝑤= Total work= (8×3+10× 2) × 15 = 660 𝑢𝑛𝑖𝑡𝑠 Work done in 10 days= (4×3+5× 2) × 10 = 220 𝑢𝑛𝑖𝑡𝑠 Let the number of more women required be x Then 2 × (5 + 𝑥) × 11 = 440 x=15

8 men and 10 women can do a work in 15 days while 10 men and 18 women can do that work in 10 days. 4 men and 5 women started the work and after 10 days all men left the work then find how many more women would be required to complete the whole work in 21 days?

Answer: B. B. 15

Explanation

8 men and 10 women can do a work in 15 days while 10 men and 18 women can do that work in 10 days. 4 men and 5 women started the work and after 10 days all men left the work then find how many more women would be required to complete the whole work in 21 days?

Answer: B. B. 15

Explanation