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RBI Grade B Officer (General / DEPR / DSIM) 2019 · Question 20 of 120

A tank contains 384 liters mixture of milk & water in the ratio of 15 : 17. If X liters of mixture taken out and (X – 14) liters of milk & (X – 34) liters of water added in remaining mixture so ratio of milk & water becomes equal. Find quantity of milk in original mixture is what percent of total final mixture?

Quantitative Aptitude

  1. AA. 40%
  2. BB. 35%
  3. CC. 45%Correct
  4. DD. 50%
  5. EE. 25%

Answer: C. C. 45%

Explanation

Total milk in mixture = 384 × 32 = 180 liters Total water in mixture = 384 × 32 = 204 𝑙𝑖𝑡𝑒𝑟𝑠 ATQ – 180 − 𝑋 ×15 32 +(𝑋−14) 204−𝑋 ×17 32+(𝑋−34) = 180 − 𝑋 × 15 32 + (𝑋−14) = 204 −𝑋 × 17 32 + (𝑋−34) 𝑋 16 = (24 −20) X = 64 liters Total final mixture = 180 – 64 × 32 + (64 −14) + 204 − 64 × 32 + (64 −34) = 200 + 200 = 400 liters Required percentage = 400 × 100 = 45%

Source: RBI Grade B 2019 Phase-I recollected paper with answers and solutions (Adda247 compilation) · memory-based

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