A and B can complete a piece of work in 12 days and 18 days respectively. They start working together, but after 4 days, A leaves the work. In how many days will B alone complete the remaining work?

Explanation

​ Information Given: Time taken by A = 12 days Time taken by B = 18 days They work together for 4 days After that, A leaves Concept/Formula Used: Work done in 1 day = 1 / Time Total Work = LCM of 12 and 18 = 36 units Explanation: Work done by A in 1 day = 36 / 12 = 3 units Work done by B in 1 day = 36 / 18 = 2 units Together work per day = 3 + 2 = 5 units Work done in 4 days = 5 × 4 = 20 units Remaining work = 36 − 20 = 16 units Now B alone completes remaining work: Required days = 16 / 2 = 8 days