RBI Assistant 2022 · Question 118 of 118
From the given statements, G has 3 more candies to A, but not study in QZ and TR. G does not have odd number of candies. Here we get 2 possibilities i.e., Case 1 and Case 2. H has studies in MR. The one who has 5 more candies to A has study in MR. Which means the person who study in MR has 26 and 36 candies in case 1 and in case 2 respectively. D has fewer candies to A and is in a multiple of 9. The one who study in GD have 6 more candies to the one who have study in ST. E has prime numbered candies that is 4 more to C. (From this condition we have only one option that E has 31 candies and C has 27 candies). And D has 18 candies. F has more candies to B. The one who has 21 candies does not study in ST. The one who studies in XS has 1.5 times of candies to the one who studies in GD. From this condition Case 2 is ruled out now. The one who studies in PQ has 4 less candies to the one who studies in QZ. The one who has 2nd maximum number of candies among all does not study in TR. So, the final arrangement is-
Source: RBI Asst Mains 2022 Memory Based English Paper (Adda247) · memory-based
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