MPSC State Service 2021 · CSAT · Question 35 of 73

4.9 g of H2SO4 is present in V cm3 0.025 N solution of sulphuric acid, then V = ________.

Reading Comprehension

Answer: C. 4000

4.9 g H2SO4 = 0.05 mol = 0.1 equivalents; at 0.025 N, V = 0.1/0.025 = 4 litres = 4000 cm3: the key's answer is (c).

Source: MPSC Rajyaseva Prelims 2021 – CSAT Paper II (Set D), official paper

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