MPSC State Service 2020 · CSAT · Question 60 of 77
Quantitative Aptitude
(11P+33) divisible by 9 gives 2P+6 = 0 mod 9, i.e. P = 6 mod 9; smallest natural P is 6.
Source: MPSC Rajyaseva Prelims 2020 – CSAT Paper II (Set C), official paper
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