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ibps-so 2025 · Question 90 of 271

In the number ‘435673538’, the digit which are less than 6 is subtracted by 2 and rest all the digits are subtracted by 1. Now remove all the repeated digits and then find the difference between sum of odd digits and sum of even digits in the new number formed after rearrangement?

  1. A5
  2. B4Correct
  3. C8
  4. D12
  5. E3

Answer: B. 4

Explanation

435673538 After applying the operation: 213561317 Removing the repeated digits: 2567 Difference between sum of odd digits and sum of even digits: 12-8 = 4 Solutions (91-95): Floors Persons Subjects 8 H Philosophy 7 C Hindi 6 B Chemistry 5 A Science 4 F English 3 E Biology 2 G Physics 1 D Mathematics

Source: IBPS SO Prelims Memory Based 2025 (held 30 Aug 2025, Shift 1) - BankersAdda · memory-based

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