A vessel contains 72 liters mixture of milk and water in the ratio of 5 : 3 respectively. 40 liters mixture is taken out and x liters of pure added in the remaining mixture. If the quantity of milk becomes 7 times of the water in the final mixture, then find the value of x?

Explanation

Information Given: Total mixture = 72 liters Ratio of milk to water in mixture = 5 : 3 40 liters of mixture is taken out x liters of pure milk is added Final ratio of milk to water becomes 7 : 1 Concept/Formula Used: Initial quantities of milk and water = (ratio parts / total parts) × total mixture Mixture taken out contains milk and water in the same ratio Milk and water remaining after removal = initial quantity – removed quantity Explanation: Initial milk = (5/8)×72 = 45 liters Initial water = (3/8)×72 = 27 liters Milk removed = (5/8)×40 = 25 liters Water removed = (3/8)×40 = 15 liters Milk remaining = 45 –25 = 20 liters Water remaining = 27 –15 = 12 liters After adding x liters of pure milk, milk becomes 20 + x liters, water remains 12 liters Final ratio of milk to water = (20 + x) / 12 = 7/1 Cross multiply: 20 + x = 7 × 12 = 84 x = 84 – 20 = 64 liters Solutions (119-124): Let the number of orders delivered by Swiggy in A and Zomato in B be 5a and 3a respectively. The number of orders delivered by Swiggy in C = 20 + 3a Let the number of orders delivered by Zomato in A be b The number of orders delivered by Swiggy in B = b The number of orders delivered by Zomato in C = 5𝑎 × 100 = 𝑎 Given, 5a + b = 150…..(I) And (b + 3a + a)/3 = 130/3 4a + b = 130 ….(II) From I & II a = 20 and b =50 Cities Zomato Swiggy A 50 100 B 60 50 C 20 80