ibps-so 2023 · Question 120 of 323
ATQ, Let number of Dolls Toys sold on Thrusday Friday and Saturday be '6x', '5x'and '7x' respectively. Let number of Cars Toys sold on Thrusday Friday and Saturday be '3y', '5y'and '4y' respectively. ATQ; 6x + 5x + 7x = 720 - 360 e e Or, 18x = 360 So, x = 20 Also, 3y + 5y + 4y = 360 Or, 12y = 360 So, y = 30 So, number of Doll Toys sold on Thrusday = 6 × 20 = 120 And, number of Car Toys sold on Thrusday = 3 × 30 = 90 So, total number of Toys sold on Thrusday = 120 + 90 = 210 Similarly, Required difference = 120 - 90 = 30
Source: IBPS SO Prelims Memory Based 2023 (AFO/IT/HR/Marketing) - ixamBee · memory-based
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