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ibps-so 2020 · Question 252 of 351

In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer. I. 3x2 - 8x - 51 = 0 II. 4y2 - 25y + 39 = 0

  1. Aif x > y
  2. Bif x < y
  3. Cif x ≤ y
  4. Dif x ≥ y
  5. Eif x = y or the relationship cannot be establishedCorrect

Answer: E. if x = y or the relationship cannot be established

Explanation

I. 3x2 - 8x - 51= 0 Pairs = -17, 9 And now dividing by a and by changing the sign we get, x = 5.6, -1 II. 4y2 – 25y + 39 = 0 Pairs = -12, -13 And now dividing by a and by changing the sign we get, y = 3, 3.25 Hence, the relationship between x and y cannot be established.

Source: IBPS SO Prelims Memory Based 2020 (IT/AFO/HR/Marketing) - ixamBee · memory-based

← Q251View full paper (351 questions)Q253 →

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