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  9. Q67

ibps-rrb-os1 2025 · Question 67 of 71

119% of 601 + (7/13) × √2197 = ?

Approximation

  1. A748Correct
  2. B731
  3. C762
  4. D719
  5. E785

Answer: A. 748

Explanation

≈120%×600 + (7/13)×√2197. 120%×600=720. √2197=13 (12³=1728, 13³=2197). (7/13)×13=7. But √2197 not cube root. √2197≈46.87. (7/13)×46.87≈25.2. Total≈720+25≈745≈748. Answer (a) 748.

Source: IBPS RRB PO Pre 2025 Practice Paper — Memory-Based Pattern (22nd November 2025, 2nd Shift, Oliveboard) · memory-based

← Q66View full paper (71 questions)Q68 →

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