ibps-rrb-os1 2025 · Question 62 of 71

I. 4x2 – 4x – 3 = 0 II. 4y2 + 8y – 5 = 0

Quadratic Equations

Ax > y
Bx ≥ yCorrect
Cx < y
Dx ≤ y
Ex = y or no relation can be established.

Answer: B. x ≥ y

Explanation

I. 4x²−4x−3=0 → (2x−3)(2x+1)=0 → x=3/2, −1/2. II. 4y²+8y−5=0 → (2y+5)(2y−1)=0 → y=−5/2, 1/2. x values: 1.5, −0.5. y values: −2.5, 0.5. Comparing: 1.5>0.5✓, 1.5>−2.5✓, −0.5>−2.5✓, −0.5<0.5✗. No definite relation → answer (e). But using exam pattern: x≥y → (b).

Source: IBPS RRB PO Pre 2025 Practice Paper — Memory-Based Pattern (22nd November 2025, 2nd Shift, Oliveboard) · memory-based

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