ibps-rrb-os1 2024 · Question 56 of 270

I. J >= F II. G = G

Syllogism

AOnly conclusion II is true.
BBoth conclusions I and III are true.
COnly conclusion I is true
DBoth conclusions II and III are true.Correct
EAll conclusions I, II and III are true.

Answer: D. Both conclusions II and III are true.

Explanation

F = E ≥ H ≤ I ≤ J No relationship can be established between J and F. Hence conclusion I is not true. G = H ≤ E G ≤ E. Hence conclusion II is true. G = H ≤ E = F F ≥ G. Hence conclusion III is true.

Source: IBPS RRB PO Prelims 2024 Memory Based Paper Shift 2 — Answer Key & Detailed Solutions (memory-based compilation, ixamBee) · memory-based

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