The speed of train A is 180 km/hr and the train can cross a pole in 4 seconds. Train A can cross a man who sitting in train B in 10 seconds, while both train running in same direction. Quantity I: Sp…

Question

The speed of train A is 180 km/hr and the train can cross a pole in 4 seconds. Train A can cross a man who sitting in train B in 10 seconds, while both train running in same direction. Quantity I: Speed of train B (in m/sec.). Quantity II: If speed of train A is decrease by 20 m/sec., then find the new speed of train A (in m/sec.)

PYQPulse · Accepted Answer

Quantity I = Quantity II or no relation

PYQPulse · Answer

Explanation: Speed of train A (in m/sec.) = 180 × 5 18 = 50 m/sec . Length of train A = 50 × 4 = 200 meters Relative speed of train A and B = 200 10 = 20 m/sec. So, speed of train B = 50 – 20 = 30 m/sec. Quantity I: Speed of train B = 30 m/sec. Quantity II: New speed of train A = 50 – 20 = 30 m/sec. So. Quantity I = Quantity II

Answer: E. Quantity I = Quantity II or no relation

Explanation

Answer: E. Quantity I = Quantity II or no relation

Explanation