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  9. Q250

ibps-rrb-os1 2024 · Question 250 of 270

The height of a cone is equal to the height of a cylinder. The curved surface area of the cylinder is 616 cm2 and the height of the cylinder is two times of the its radius. The radius of the cone is 50% of the radius of the cylinder. Quantity I: Find the difference between total surface area and curved surface area of the cylinder. Quantity II: Find the curved surface area of the cone.

English (misc)

  1. AQuantity I > Quantity II
  2. BQuantity I < Quantity IICorrect
  3. CQuantity I ≥ Quantity II
  4. DQuantity I ≤ Quantity II
  5. EQuantity I = Quantity II or no relation

Answer: B. Quantity I < Quantity II

Explanation

Let radius of cylinder = x cm So, height of the cylinder = 2x cm 2 × 22 7 × r × h = 616 x2 = 49 x = 7 So, height of the cylinder = 14 cm Cone radius = 7 × 1 2 = 3.5 cm Quantity I: Total surface area of cylinder = 2 × 22 7 × 7 × 21 = 924 cm2 Required difference = 924 – 616 = 308 cm2 Quantity II: lateral height of cone = √196 + 12.25 = √208.25 cm Curved surface area of the cone = 22 7 × 7 × √208.25 = 317.47 cm2 (approx.) So, Quantity I < Quantity II

Source: IBPS RRB PO Mains Previous Year Paper 2024 (BankersAdda) · memory-based

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