ibps-rrb-os1 2024 · Question 250 of 270
English (misc)
Let radius of cylinder = x cm So, height of the cylinder = 2x cm 2 × 22 7 × r × h = 616 x2 = 49 x = 7 So, height of the cylinder = 14 cm Cone radius = 7 × 1 2 = 3.5 cm Quantity I: Total surface area of cylinder = 2 × 22 7 × 7 × 21 = 924 cm2 Required difference = 924 – 616 = 308 cm2 Quantity II: lateral height of cone = √196 + 12.25 = √208.25 cm Curved surface area of the cone = 22 7 × 7 × √208.25 = 317.47 cm2 (approx.) So, Quantity I < Quantity II
Source: IBPS RRB PO Mains Previous Year Paper 2024 (BankersAdda) · memory-based
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