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ibps-rrb-os1 2021 · Question 87 of 173

A rectangle ABCD is given, whose sides AB and CD are equal. It is given that BC = X and CD = 2X+5. If area of rectangle is 168 sq. cm., then find the length of AB.

Quantitative Aptitude (misc)

  1. A17 cm
  2. B21 cmCorrect
  3. C15 cm
  4. D23 cm
  5. ECND

Answer: B. 21 cm

Explanation

Area of rectangle = X(2X + 5) = 168 2X2 + 5X − 168 = 0 2X2 − 16X + 21X − 168 = 0 2X(X − 8) + 21(X − 8) (2X + 21)(X − 8) = 0 X = 8 So, AB = CD = 2 × 8 + 5 = 21 cm

Source: IBPS RRB PO Mains 2021 Memory Based Paper (Adda247/BankersAdda) · memory-based

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