I. 4x2 – 4x + 1 = 0 II. 4y2 – 16y + 7 = 0

Explanation

I. 4x2 – 4x + 1 = 0 ⇒ 4x2 – 2x – 2x + 1 = 0 ⇒ 2x(x – 1) – 1(2x – 1) = 0 ⇒ (2x – 1)(2x – 1) = 0 ⇒ x = 1/2, 1/2 II. 4y2 – 16y + 7 = 0 ⇒ 4y2 – 2y – 14y + 7 = 0 ⇒ 2y(2y – 1) – 7(2y – 1) = 0 ⇒ (2y – 7)(2y – 1) = 0 ⇒ y = 7/2, 1/2 Hence, x ≤ y. Alternate Method: if signs of quadratic equation is -ve and +ve respectively then the roots of equation will be +ve and +ve. So, roots of first equation = x = 1/2, 1/2 So, roots of second equation = y = 7/2, 1/2 After comparing we can conclude that x ≤ y. IBPS RRB Scale I 2021 Prelims Memory Based Paper