ibps-rrb-os1 2017 · Question 51 of 74
Ratio & Proportion
I. 𝑥2 − 7𝑥 + 12 = 0 𝑥2 − 4𝑥 − 3𝑥 + 12 = 0 𝑥(𝑥 − 4) − 3(𝑥 − 4) = 0 (𝑥 − 3)(𝑥 − 4) = 0 𝑥 = 3, 4 II. 3𝑦2 − 11𝑦 + 10 = 0 3𝑦2 − 6𝑦 − 5𝑦 + 10 = 0 3𝑦(𝑦 − 2) − 5(𝑦 − 2) = 0 (3𝑦 − 5)(𝑦 − 2) = 0 𝑦 = 2, 5 3 ∴ 𝑥 > 𝑦
Source: IBPS RRB PO Prelims 2017 Memory Based Paper (Adda247) · memory-based
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