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ibps-rrb-os1 2017 Β· Question 41 of 74

There are 3 consecutive odd numbers and 3 consecutive even numbers. The smallest even number is 9 more than largest odd number. If the square of average of all the 3 given odd number is 507 less than the square of the average of all the 3 given even number, what is the smallest odd number.

Average

  1. A11Correct
  2. B13
  3. C17
  4. D19
  5. E9

Answer: A. 11

Explanation

Let a consecutive odd numbers = π‘₯ – 2, π‘₯ and π‘₯ + 2 and consecutive even numbers = 𝑦 – 2, 𝑦, 𝑦 + 2 So, 𝑦 – 2 = 9 + π‘₯ + 2 𝑦 – π‘₯ = 13 … (i) and (π‘₯)2 + 507 = (𝑦)2 𝑦2 βˆ’ π‘₯2 = 507 (π‘₯ + 𝑦)(𝑦 βˆ’ π‘₯) = 507 (π‘₯ + 𝑦) = 507 13 β‡’ π‘₯ + 𝑦 = 39 … (𝑖) Solving (i) and (ii) 𝑦 = 26 and π‘₯ = 13 so smallest odd numbers = π‘₯ – 2 = 13 – 2 = 11

Source: IBPS RRB PO Prelims 2017 Memory Based Paper (Adda247) Β· memory-based

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