ibps-rrb-oa 2022 · Question 57 of 181
Boats and streams
Let speed of boat in still water be x kmph And distance be ‘D’ km ATQ 𝐷 =5 𝑥−3 D = 5 (𝑥 − 3) − − − − − (𝑖) And, 𝐷 =2 𝑥+3 D = 2(𝑥 + 3) − − − −(𝑖𝑖) From (i) and (ii) 5(𝑥 − 3) = 2(𝑥 + 3) 5x – 15 = 2x + 6 3𝑥 = 21 ⇒ 𝑥 = 7 𝑘𝑚/ℎ𝑟 So, required distance = 5 × (7 − 3) = 20 𝑘𝑚
Source: IBPS RRB Clerk Prelims 2022 Memory Based Paper (Adda247) · memory-based
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